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In K₂Cr₂O₇: K is +1 (×2 = +2), O is -2 (×7 = -14). Total charge = 0. So 2 + 2x - 14 = 0 → 2x = 12 → x = +6. The oxidation state of Chromium (Cr) in potassium dichromate is +6. This is why K₂Cr₂O₇ is a strong oxidizing agent.